Question

3(x - 2)² – 2(x - 2) - 8​

Answer 1

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3(x - 2)^2 - 2(x - 2) - 8

let

x - 2 =t

3t^2 -2t - 8

3t^2 - 6t +4t - 8

(3t +4)(t -2)

on putting

x - 2 = t

we get

( 3x - 2)(x - 4)

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Hope it may helps you

Answer 2

Answer:3( x^2+4-4x)-2(x-2)-83x^2+12-12x-2x+4-83x^2-14x+8

By Middle term splitting method

3x^2 -12x-2x+8 = 03x(x-4)-2(x-4) = 0(3x-2)(x-4) = 0

Put each value equals to "0" b/c we don't know which value is 0 in both of them so the resultant come 0.

(3x-2) = 0

3x = 2

x = 2/3

nd x-4 = 0

x = 4

HOPE IT WILL HELP U DUDE

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