Question

3(x+2)²=27.this is a quadratic equation . find the roots for x. ​

Answer 1

Answer:

3(x+2)^2=27

3(x^2+2x+4)=27

x^2+2x+4=9

x^2+2x-5=0

a=1, b=2 ,c=-5

roots =[-b+-√(b^2-4ac)]/2a

=[-2+-√(4+20)]/2

=[-2+-√24]/2

=[-2+-√(6*4)]/2

=[-2+-2√6]/2

= -1+-√6

=-1+√6. or. -1-√6

hence roots are (-1+√6) or (-1-√6)