3(x+2)^2 - 5(x+2)+2 factorize
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let x+2=y
3y^2-5y+2=0
3y^2-2y-3y+2=0
y(3y-2)-(3y-2)=0
(3y-2)(y-1)=0
y=3/2 y=1
x+2=3/2 x+2=1
x=-1/2 x=-1
3y^2-5y+2=0
3y^2-2y-3y+2=0
y(3y-2)-(3y-2)=0
(3y-2)(y-1)=0
y=3/2 y=1
x+2=3/2 x+2=1
x=-1/2 x=-1
vishalsaini:
i think you made a mistake
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0
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