Question

(3/x-2)-(2/x-3)=(4/x-3)-(3/x-1)​

Answer 1

Step-by-step explanation:

Firstly, we will solve the LHS.

$( \frac{3}{x} - 2) - ( \frac{2}{x} - 3)$

$\frac{3}{x} - 2 - \frac{2}{x} + 3$

$\frac{3}{x} - \frac{2}{x} - 2 + 3$

$\frac{1}{x} + 1$

Now, we will solve the RHS.

$( \frac{4}{x} - 3) - ( \frac{3}{x} - 1)$

$\frac{4}{x} - 3- \frac{3}{x} + 1$

$\frac{4}{x} -\frac{3}{x} - 3 + 1$

$\frac{1}{x} - 2$

Hence, the LHS part is not equal to RHS.

So, this equation is not equal.