Math, asked by anushankar60520, 5 months ago

3(x-2)+2(x-3)=5(x-1)-7(x-4). find the value of x​

Answers

Answered by ItzWhiteStorm
113

\Large\underline{\blue{\mathfrak{Question:}}}

\dashrightarrow 3(x-2)+2(x-3)=5(x-1)-7(x-4). find the value of x.

\Large \underline{\blue{\mathfrak{To\:Find:}}}

\:  \:  \:  \:  \:  \: \:\:\:\:\:\:  \bullet \: \sf{Value\:of\:x.}

\Large \underline{\blue{\mathfrak{Solution:}}}

 \:   \:  \:   : : \implies\sf{3(x-2)+2(x-3)=5(x-1)-7(x-4)}

 \:  \:  \:  \: \:  \:   : :  \implies\sf{3x-6+2x-6=5x-5-7x + 28}

 \:  \:  \:  \:  \:  \:  \:  \:  \: :  :  \implies \sf{5x - 12 =  - 2x + 23}

 \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \: \:   :  : \implies \sf{5x  + 2x = 23 + 12}

 \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  :  :  \implies \sf{7x = 35}

 \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  : :  \implies\sf{x =\cancel\frac{35}{7} }

 \:  \:  \:  \:   \:  \:  \:  \: \:  \:  \:  \:  : : \implies\sf{ x= 5}

Thus,The value of x is 5.

__________________________________

Answered by TheMist
188
\huge \sf \underline{Answer}:
\large \implies x = 5
 \\ \\ \huge \sf \underline{Solution}:
\large \sf \underline{Given}:
 \: \: \: ⇝ 3(x-2)+2(x-3)=5(x-1)-7(x-4)
\\ \large \sf \underline{To \: Find}:
The value of x​
━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

\sf \implies 3(x-2)+2(x-3)=5(x-1)-7(x-4) \\ \implies \sf 3x-6+2x-6=5x-5-7x+28 \\ \implies \sf 5x -12 = -2x+23 \\ \implies 5x+2x=23+12 \\ \implies\sf 7x=35 \\ \implies \sf x=\cancel{\frac{35}{7}} \\ \sf \implies \boxed{x=5}
━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
Therefore,
The value of x is 5.
━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
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