Question

3(x-2)+2(x-3)=5(x-1)-7(x-4)
$3(x - 2) + 2(x - 3) = 5(x - 1) - 7(x - 4)$
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Answer 1

$= > 3 (x-2) + 2(x-3) = 5(x - 1) - 7(x - 4)$

$= > 3x +3× (-2) + 2(x − 3) = 5(x - 1)- 7 (x-4)$

$= > 3x + 3× (-2) + 2x + 2 × (-3) = 5 (x- 1) - 7 (x-4)$

$= > \: 3x + 3 × (-2) + 2x + 2 × (-3) =5x - 5 - 7 (x-4)$

$= > 3x + 3x (-2) + 2x + 2 × (-3) = 5x- 5- 7x - 7× (-4)$

$= > 3x −6+2x+ 2 × (-3) = 5x – 5 – 7x- 7 \times (-4)$

$= > 3x −6+2x - 6 = 5x -5-7x - 7 \times ( - 4)$

$= > 5x-12=5x - 5 - 7x - 7 × (-4)$

$= > 5x-12 = 5x -5-7x +28$

$= > 5x - 12 + 2x = 23$

$= > 5x - 12 = - 2x - 5 + 28$

$= > 5x - 12 = -2x + 23$

$= > 5x - 6-6= 5x -5-7x-7x (-4)$

$= > 5x + 2x = 23 + 12$

$= > 7x = 23 + 12$

$= > 7x = 35$

$= > x = \frac{35}{7}$

$\color{lime}\ \boxed{\colorbox{black}{final \: result : \: x = 5}}$