Question

3 X + 2 Y =11 and 2x + 3 Y = 4 solve by elimination method​

Answer 1

Answer:

$3x + 2y = 11 \: \: \: \: \: .........(1) \\ 2x + 3y = 4 \: \: \: \: \: .............(2) \\ on \: multiplying \: (1) \: by \: 3\: and \: (2) \: by \: 2\\ 9x + 6y = 33 \\4 x + 6y = 8 \\ and \: substracting \:(2) from \: (1) \\ 5x = 25 \\ x = 5 \\ and \:2 y = 11 - 3 \times 5 \\ y = - 2$

Answer 2

Answer

The values are :

x = 5

y = -2

Given :

The equations are :

• 3x + 2y = 11
• 2x + 3y = 4

To Find :

• The value of x and y

Solution :

$\sf {3x + 2y = 11} \\ \sf\implies6x + 4y = 22 \: .........(1)$

and

$\sf{2x + 3y = 4} \\ \implies \sf6x + 9y = 12 \: ...........(2)$

Subtracting (2) from (1) we have :

$\sf \implies6x + 4y - 6x - 9y = 22 - 12 \\ \sf \implies - 5y = 10 \\ \sf \implies y = - \dfrac{10}{5} \\ \sf \implies \boxed{\sf y = - 2}$

Putting the value of y in equation (1)

$\sf \implies6x + 4( -2) = 22 \\ \sf\implies6x - 8 = 22 \\ \sf \implies6x = 22 + 8 \\ \sf\implies6x = 30 \\ \implies\boxed{ \sf x = 5}$

Verification :

Now putting both the values in one of the equation given in the question :

$\sf3 \times 5 + 2( - 2) = 11 \\ \sf\implies15 - 4= 11 \\ \sf \implies11 = 11$