Question

3) x + 2y = -1; 2x – 3y = 12
(4) 6x – 4y = -12; 8x – 3y = -2
(5) 4m + 6n = 54; 3m + 2n = 28
(6) 2x + 3y = 2; x – Ž =
2​

Answer 1

Answer:

(3)

$x + 2y - 1 \: \: \: \: (i) \\ 2x - 3y = 12 \: \: \: (ii) \\ froma(i)x = - 1 - 2y \: \: (iii) \\ substituting \: thi \: value \: of \: x \: in \: \\ (ii)we \: get \\ 2( - 1 - 2y) - 3y = 2 \\ = - 2 - 4y - 3y = 12 \\ = 7y = 14 \\ = y = - 2 \\ putting \: y = - 2 \: in \: (iii) \: we \: get \: \\ x = - 1 \times 2 = - 1 + 4 = 3 \\ hencethe \: required \: solution \: is \: \\ x = 3 \\ y = - 2$