Question

3(x-3)=5(2x+1) with transposing​

Answer 1

Step-by-step explanation:

Question:- 3(x-3)=5(2x+1) with transposing

Solution:-

Given 3(x – 3) = 5(2x + 1)

On simplifying the brackets we get,

3x – 9 = 10x + 5

Now transposing 10x to LHS and 9 to RHS

3x – 10x = 5 + 9

-7x = 14

Now dividing both sides by -7 we get

-7x/-7 = 14/-7

x = -2

Verification:

Substituting x = -2 in the given equation we get

3 (-2 – 3) = 5 (-4 + 1)

3 (-5) = 5 (-3)

-15 = – 15

Thus LHS = RHS

Hence, verified.

:)