3^(x)-3^(x-1)=18,find value of x^x
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Answered by
1
hey mate
3^(x)-3^(x-1)=18,find value of x^x
answer:
3^(x)-3^(x-1)=18,
3^x(1-1/3)=18
3^x (3-1)/3=18
3^x(2/3)=18
3^x=18×3/2
3^x= 9×3
=3×3×3
3^x = 3³
x= 3.
now,
x^x= 3³
= 27
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Answered by
4
We take some help from Laws of Indices
a^(b+c)=a^b.a^c.
so,
3^x-3.^x-3^(-1)
Take 3^x common,3^x(1-3^(-1))
3^-1 is 1/3 or 0.66
3^x(1-1/13)=18
3^x(2/3)=18
3^x=27
Represent 27 as a no of 3's , 27=3*3*3.
3^x=3^3
x=3
Anonymous:
hlow
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