3^x+3^-x=2 find the value of x
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Answered by
1
Step-by-step explanation:
x
4
−x
3
+x
2
+3x−5
(2+3i)
4
−(2+3i)
3
+(2+3i)
2
+3(2+3i)−5
(2+3i)
4
:−119−120i
(2+3i)
3
:−46+9i
(2+3i)
2
:−5+12i
=(−119−120i)+46−9i+(−5+12i)+6+9i−5
=−119−120i+46−9i−5+12i+6+9i−5
=−120i−9i+12i+9i−119+46−5+6−5
=−108i−119+46−5+6−5
=−77−108i
Answered by
30
3^x+3^-x=2 find the value of x
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