Question

3^x+3^-x=2 solve the equation​

Answer 1

Answer:

x = 0

Step-by-step explanation:

3^x + 1/3^x = 2

by taking LCM

(3^x)^2 + 1 = 2× 3^x

Let 3^x = y

therefore

y^2 + 1 = 2y

By factorising we get

y = 1

therefore

3^x = y = 1

3^x = 1

x = 0

Answer 2

Answer:

answer is 0 just substitute......

actually there is another way

put 3^x=t

then 3^-x=1/t

thus the equation becomes

t+1/t=2

multiplying both sides with t we get t^2+1-2t=0

=>(t-1)^2=0

ie:t=1

=>3^x=1

ie:x=0

hence solved