Question

3^x+3^-x=2, solve the following quations.
chapter:- Quadratic equations

Answer 1

Answer:

x = 0

Step-by-step explanation:

$3^{x}$ + $3^{-x}$ = 2

$3^{x}$ = y

y + $\frac{1}{y}$ = 2 ..... (1)

Multiply (1) by "y"

y² + 1 = 2y

y² - 2y + 1 = 0

(y - 1)² = 0

y = 1

$3^{x}$ = 1 ===> x = 0