Question

3^x+3^-x=2
$3 {}^{x} + 3 {}^{ - x} = 2$
quadratic equation find x​

Answer 1

Answer:

${3}^{x} + {3}^{ - x} = 2$

Step-by-step explanation:

$let \: {3}^{x} = y \\ according \: to \: the \: question \: \\ {y}^{2} + 1 = 2y \\ {y}^{2} - 2y + 1 = 0 \\( y - 1)^{2} = 0 \\ y = 1 \\ \\ y = {3}^{x} = 1 \\ {3}^{x} = {3}^{0} \\ x = 0$