Question

3^x+ 3^x+ 3^x =243 find x..
please answer I have an exam in 1 hour​

Answer 1

Answer:

Given that,

3^(x - y) = 27 ….(i)

3^(x + y) = 243 ….(ii)

To solve this equations, you first need to know a law-

If a^x = a^y, then x = y.

From equation (i), we get -

3^(x - y) = 27

=> 3^(x - y) = 3^3 [From the law described above]

=> x - y = 3

=> y = x - 3 … (iii)

Now, from equation (ii), we get -

3^(x + y) = 243

=> 3^(x + y) = 243

=> 3^(x + y) = 3^5

=> x + y = 5 [From the law described above]

=> x + (x - 3) = 5 [Because, from equation (iii) y = x - 3 ]

=> x + x - 3 = 5

=> 2x - 3 = 5

=> 2x = 5 + 3

=> 2x = 8

=> x = 8/2

=> x = 4

So, x = 4

Please mark this answer as brainliest !

Answer 2

Answer:

Answer:

The value of x is 4.

Given:

The equation is,

3^x+3^x+3^x=243

Solution:

3^x+3^x+3^x=243

3^x(1+1+1)=243

3^x(3)=243

3^(x+1)=243

3^(x+1)=3⁵

x+1=5

x=4

So the value of x is 4.

Step-by-step explanation:

Hope it helps you......