Question

3(x-3)(x+4)+3(x+2)(x-4)=19(x-4)(x-3)

Answer 1

Answer:

Let's solve your equation step-by-step.

3(x−3)(x+4)+3(x+2)(x−4)=19(x−4)(x−3)

Step 1: Simplify both sides of the equation.

6x2−3x−60=19x2−133x+228

Step 2: Subtract 19x^2-133x+228 from both sides.

6x2−3x−60−(19x2−133x+228)=19x2−133x+228−(19x2−133x+228)

−13x2+130x−288=0

For this equation: a=-13, b=130, c=-288

−13x2+130x+−288=0

Step 3: Use quadratic formula with a=-13, b=130, c=-288.

x=

−b±√b2−4ac

2a

x=

−(130)±√(130)2−4(−13)(−288)

2(−13)

x=

−130±√1924

−26

x=5+

−1

13

√481 or x=5+

1

13

√481

Answer:

x=5+

−1

13

√481 or x=5+

1

13

√481