Question

3
x - 3x² + 3x + 7 = x+1) (ax^2 +bx+c).
find atbtc​

Answer 1

Answer:

${x}^{3} - 3 {x}^{2} + 3x + 7 = (x + 1)(a {x}^{2} + bx + c)$

RHS,

$a {x}^{3} + b {x}^{2} + cx + a {x}^{2} + bx + c = \\ a {x}^{3} + (a + b) {x}^{2} + (b + c)x + c$

comparing with LHS,

$a = 1 \\ a + b = - 3 \\ so \: \: b = - 3 - 1 = - 4 \\ b + c = 3 \\ so \: \: c = 3 + 4 = 7$

Answer 2

Step-by-step explanation:

$\huge{\underline{\underline{\boxed{\sf{Answer}}}}}$

x - 3x² + 3x + 7 = x+1) (ax² +bx+c).

$\huge{\underline{\underline{\boxed{\sf{Answer}}}}}$

${x}^{3} - 3 {x}^{2} + 3x + 7 = (x + 1)(a {x}^{2} + bx + c)$

RHS,

$a {x}^{3} + b {x}^{2} + cx + a {x}^{2} + bx + c = \\ a {x}^{3} + (a + b) {x}^{2} + (b + c)x + c$

comparing with LHS,

$a = 1 \\ a + b = - 3 \\ so \: \: b = - 3 - 1 = - 4 \\ b + c = 3 \\ so \: \: c = 3 + 4 = 7$