3(x – 4)^2 - 5(x - 4) = 12
Answers
Answer:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
3*(x-4)^2-5*(x-4)-(12)=0
Step by step solution :
STEP
1
:
Equation at the end of step 1
((3•((x-4)2))-5•(x-4))-12 = 0
STEP
2
:
Equation at the end of step 2
(3 • (x - 4)2 - 5 • (x - 4)) - 12 = 0
STEP
3
:
Trying to factor by splitting the middle term
3.1 Factoring 3x2-29x+56
The first term is, 3x2 its coefficient is 3 .
The middle term is, -29x its coefficient is -29 .
The last term, "the constant", is +56
Step-1 : Multiply the coefficient of the first term by the constant 3 • 56 = 168
Step-2 : Find two factors of 168 whose sum equals the coefficient of the middle term, which is -29 .
-168 + -1 = -169
-84 + -2 = -86
-56 + -3 = -59
-42 + -4 = -46
-28 + -6 = -34
-24 + -7 = -31
-21 + -8 = -29 That's it
Step-by-step explanation:
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x=8/3;x=7
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