Question

3(x-4)²-5(x-4)=12 find roots​

Answer 1

Answer:

$(x - 4)(3x - 12 - 5) = 12$

$(x - 4)(3x - 17) = 12$

$3 {x}^{2} - 29x + 68 - 12 = 0$

$3 {x}^{2} - 29x + 56 = 0$

$3 {x}^{2} - 21x - 8x + 56 = 0$

$3 x(x - 7) - 8(x - 7)$

$(x - 7)(3x - 8)$

hope it helps ♥️