Question

3(x-4)^2-5(x-4)=12 what are the roots​

Answer 1

Step-by-step explanation:

assume that x-4 =t

3t^2-5t-12=0

t =13/6 and -1/3

x-4=13/6 x-4 =-1/3

x=13/6+4 ×=-1/3+4

x=37/6 x =11/3