Question

3(x-4)^-5(x-4)=12 Find the zeros of the this quadratic equation

Answer 1

Answer:

4ajdeep is my name can u

Answer 2

Answer: X = 6 (or) X = 11/3

Step-by-step explanation:

3(x - 4)^ - 5(x - 4) = 2

3(x^ + 4^ -2.x.4) - 5x + 20 = 2

3(x^ + 16 - 8x) - 5x + 20 = 2

3x^ + 48 - 24x - 5x + 20 =2

3x^ - 29x + 68 = 2

3x^ - 29x + 68 - 2 = 0

3x^ - 29x + 66 = 0

3x^ - 18x - 11x + 66 = 0

3x(x - 6) - 11(x - 6) = 0

(x - 6) (3x - 11) = 0

X - 6 = 0 (or) 3x - 11 = 0

X = 6 (or) X = 11/3