Question

[3√x^4y×1\3√xy7]^-4 solve and simply and positive expontial

Answer 1

Answer: $x^{-10}y^{-16}$

Step-by-step explanation:

Here the given expression is,

$(3\sqrt{x^4y}\times \frac{1}{3}\sqrt{xy^7})^{-4}$

$=(\sqrt{x^4y}\times \sqrt{xy^7})^{-4}$

$=(\sqrt{x^4y\times xy^7})^{-4}$

$=(\sqrt{x^5y^8})^{-4}$

$=(x^5y^8)^{\frac{1}{2}\times -4}$

$=(x^5y^8)^{-2}$

$=x^{-10}y^{-16}$

Answer 2

here is ur answer may it help u