Question

(3 + x – 4y)^2 wrte in expanded form

Answer 1

Step-by-step explanation:

$using \: {(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ac \\ {(3 + x - 4y)}^{2} \\ = {3}^{2} + {x}^{2} { ( - 4y)}^{2} + 2 \times 3 \ \times x + 2 \times x \times ( - 4y) + 2 \times 3 \times ( - 4y) \\ = 9 + {x}^{2} + 16 {y}^{2} + 6x + ( - 8xy) + ( - 24y) \\ = {x }^{2} + 6x + 16 {y}^{2} - 24y - 8xy + 9$

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Answer 2

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