Question

3/x + 5/y = 20/xy and 2/x + 5/y = 15/xy

Answer 1

${\bold{\huge{\textbf{\red{Answer}}}}}$

Given Ques.:

${\bold{\frac{3}{6}+\frac{5}{y}= \frac{20}{xy}}}\rightarrow(1)$

${\bold{\frac{2}{x}+\frac{5}{y}= \frac{15}{xy}}}\rightarrow(2)$

now on solving the equation (1) [taking L.C.M.]

${\bold{\frac{3y+5x}{xy}= \frac{20}{xy}}}\rightarrow(1)$

Then we get the equation as,

${\bold{\purple{3y+5x=20}}}\rightarrow(3)$

similarly on solving equation (2) we get,

${\bold{\purple{2y+5x=15}}}\rightarrow(4)$

now on solving equation (3) and (4) ny elimination method,

we get

${\bold{\boxed{\green{y=5}}}}$ and ${\bold{\boxed{\green{x=1}}}}$

Answer 2

Answer:

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