3^x×5^y=75^z
find the value of z
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3^x=(75) ^z
3^x=(25×3)^z
3^x=(5^2 ×3)^z
3^x =5^2z×3^z
3^x/3^z = 5^2z
3^x-z=5^2z
taking log both side and after simplification
log5/log3= (x-z)/2z
similarly for 5^y=(75) ^z
log5/log3 z/y-2z
since both are equal
(x-z)/2z =z/y-2z
after simplification
z=xy/y+2x
Step-by-step explanation:
i hope this answer helps u
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