3^x = 5^y = 75^z solve this
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Answer:
Given,
3x=5y=75z
3x=5y=75z=k
⇒3=k 1/x,5=k 1/y,75=k 1/z
5²×3=k 1/z
(k 1/y)² ×(k 1/x) = k 1/z
By comparing powers
⇒ 2/y + 1/x = 1/z
2x+y/xy = 1/z
∴z= xy/2x + y
[henceproved]
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