3 X + 5 Y is equals to 9 and 5 x + 3 Y is equals to 7 then find the value of x + Y please answer if you know and in full format
Answers
Answered by
1
3x + 5y = 9
5x + 3y = 7
Multiply eq1 by 5 and eq2 by 3 and subtract eq2 from eq1
15x + 25y = 45
-15x - 9y = -21
16y = 24
y = 24/16 = 3/2
Put y in eq1
3x + 5×3/2 = 9
3x = 9 - 15/2
3x = 3/2
x = 1/2
Now, x + y = 3/2 + 1/2
= 4/2 = 2
x + y = 2
Thanks
5x + 3y = 7
Multiply eq1 by 5 and eq2 by 3 and subtract eq2 from eq1
15x + 25y = 45
-15x - 9y = -21
16y = 24
y = 24/16 = 3/2
Put y in eq1
3x + 5×3/2 = 9
3x = 9 - 15/2
3x = 3/2
x = 1/2
Now, x + y = 3/2 + 1/2
= 4/2 = 2
x + y = 2
Thanks
Answered by
0
3x+5y=9 …(1)
5x+3y=7 …(2)
Let us simplify the equations by eliminating a variable
Make the coefficients of X or Y equal
Multiply equation (1) with 5 and equation (2) with 3
We get 15x+25y=45 and 15x+9y=21
Now subtract the equations, we get
(15x+25y)-(15x+9y)=(45–21)
16y=24, y= 24/16 = 3/2
Substituting the value of y in equation (1) we get
3x+5(3/2)=9
3x+15/2=9
3x=9–15/2
3x=3/2
x =1/2
x+y =3/2+1/2= 2
x+y=2
The other method is simply add equations (1) & (2)
You get
8x+8y=16
x+y=2
Answered By SUDIN
5x+3y=7 …(2)
Let us simplify the equations by eliminating a variable
Make the coefficients of X or Y equal
Multiply equation (1) with 5 and equation (2) with 3
We get 15x+25y=45 and 15x+9y=21
Now subtract the equations, we get
(15x+25y)-(15x+9y)=(45–21)
16y=24, y= 24/16 = 3/2
Substituting the value of y in equation (1) we get
3x+5(3/2)=9
3x+15/2=9
3x=9–15/2
3x=3/2
x =1/2
x+y =3/2+1/2= 2
x+y=2
The other method is simply add equations (1) & (2)
You get
8x+8y=16
x+y=2
Answered By SUDIN
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