Question

3 x 53x +k0 solve this question plz​

Answer 1

Answer:

Given (2x+7)/5−(3x+11)/2=(2x+8)/3−5

Now by taking L.C.M for 2 and 5 is 10

15(2(2x+7)−5(3x+11))/10=(2x+8)/3−5

By transposing the above equation we can write as

33x−20x=123−70

Again by transposing

X=−53/53

x=−1

Answer 2

Answer:

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