Question

3/x+8/y=-1; 1/x-2/y=2 ; xy not equal 0 find solution of the pair of equation

Answer 1

Let,

$\textbf{1 / x = X}$

And

$\textbf{1 / y = Y}$

New equations formed :-

$\textbf{3X + 8Y = -1}$ _______(1)

And

$\textbf{X - 2Y = 2}$ ______(2)

Multiply (2) with 3

3(X - 2Y) = 3(2)

3X - 6Y = 6 _______(3)

Subtract (1) and (3)

3X + 8Y - (3X - 6Y) = -1 - 6

3X + 8Y - 3X + 6Y = -7

14Y = -7

Y = -7 / 14

Y = -1 / 2

Put this value in (1)

3X + 8(-1 / 2) = -1

3X - 4 = -1

3X = -1 + 4

3X = 3

X = 1


Now,

X = 1 / x

1 = 1 / x

$\textbf{x = 1}$

Also,

Y = 1 / y

-1 / 2 = 1 / y

$\textbf{y = -2}$

Answer 2

Answer:

Step-by-step explanation: