Question

3 x cube + 10 x + 7 x upon mein x + 1

Answer 1

Answer:

$\frac {(3x^3+10x^2+7x)}{x+1}\\ \\ \\</p><p>by \: using \: factor\: theorem- \\ \\ \\</p><p>x+1= 0, x= -1\\ \\ \\</p><p>given: f(x)= 3x^3+10x^2+7x\\ \\ \\</p><p>f(-1)= 3(-1)^3+10(-1)^2+7(-1)\\ \\ \\</p><p>= -3+10-7\\ \\ \\</p><p>= -10+10= 0.\\ \\ \\</p><p>x+1\: is \:a \: factor\: of \: 3x^3+10x^2+7x$

please mark it as brainliest ❤️❤️ and follow me...