Question

3 X square + 2 root 5 minus 5 find the roots​

Answer 1

Answer:

3x^2 + 2√5-5=0

D

=b^2-4ac

=(2√5)^2 - 4(3)(-5)

= (4×5) + 60

D=80

.°. D>0, real roots

x = - b +√D/2a

= -2√5 + √80/2(3)

= -2√5 + 4√5/6

x=√5. or x = √5/3

here's your answer mark as BRAINLIEST.