Question

3 x square - 6 X + 2​

Answer 1

Step-by-step explanation:

answer is this

hope this helps u

Answer 2

Given a Quadratic equation

$3x^{2} - 6x + 2 = 0$

So we need to find out the value of X

Let us start ✓ For getting the value we will use sridhar acchariyas formula which is as follows

$x = \frac{ - b \: plus \: minus \sqrt{b ^{2} - 4ac } }{2a} \:$

So from the equation we find

a=3, b=-6 and c= 2

$x = \frac{ - ( - 6) \: plus \: minus \sqrt{( - 6) ^{2} - 4 \times 3 \times 2 } }{2 \times 3} \\ \\ = > x = \frac{6 \: plus \: minus \sqrt{36 - 24} }{6} \\ \\ = >x = \frac{6 \: plus \: minus \sqrt{12} }{6} \\ \\ = >x = \frac{6 \: plus \: minus \: \sqrt[2]{3} }{6} \\ so \: either \: \\ x = \frac{6 + \sqrt[2]{3} }{6} \: or \: x = \frac{6 - \sqrt[2]{3} }{6}$

So this are the roots of the equation or the values of x