Question

3 x square - twice √6 x+ 2 =0

Answer 1

$3 {x}^{2} - 2 \sqrt{6} x + 2 = 0 \\ 3 {x}^{2} - \sqrt{6} x - \sqrt{6} x + 2 = 0 \\ \sqrt{3} x( \sqrt{3} x - \sqrt{2} ) - \sqrt{2} ( \sqrt{3} x - \sqrt{2} ) = 0 \\{ ( \sqrt{3} x - \sqrt{2} ) }^{2} = 0 \\ x = \sqrt{ \frac{2}{3} }$
please follow me