Question

3 X square + x square + 2 X + 5 x cube + 2 X + 1 se​

Answer 1

Step-by-step explanation:

Given expression is:-

$3 {x}^{2} + {x}^{2} + 2x + 5 {x}^{3} + 2x + 1 \\ 4 {x}^{2} + 4x + 5 {x}^{3} + 1$

Just in case the question asked you to factorise the whole thing,

$4x(x + 1) + 1(x + 1) \\ (4x + 1)(x + 1)$

Therefore it is factorised.

If you wanted two solutions of x,

$4x + 1 = 0 \\ x = \frac{ - 1}{4}$

One solution is -1/4

The other is,

$x + 1 = 0 \\ x = - 1$

-1