Math, asked by binaykumar99398842, 5 months ago

3 X square + x square + 2 X + 5 x cube + 2 X + 1 se​

Answers

Answered by sujayG17
0

Step-by-step explanation:

Given expression is:-

3 {x}^{2}  +  {x}^{2}  + 2x + 5 {x}^{3}  + 2x + 1 \\ 4 {x}^{2}  + 4x + 5 {x}^{3}  + 1

Just in case the question asked you to factorise the whole thing,

4x(x + 1) + 1(x + 1) \\ (4x + 1)(x + 1)

Therefore it is factorised.

If you wanted two solutions of x,

4x + 1 = 0 \\ x =  \frac{ - 1}{4}

One solution is -1/4

The other is,

x + 1 = 0 \\ x =  - 1

-1

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