3×x×x+11×x-12=0 using b square -4ac
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Answer:
3x²+11x-12
=> a=3;b=11;c= -12
b²-4ac
= (11)²-4×3×(-12)
= 121 + 144
= 265
•°• answer :- 265
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Answered by
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Step-by-step explanation:
First find the differential of the equation:d/dx(3x^2+11x-12)
=6x+11
Discriminant:+or-√b^2-4ac
=+or-√121+4×3×12
=+or-√121+144
=+or-√265
Equate step (1) and (2) for the value of x
So, 6x+11=+or-√265
So,6x=+or-√265-11
x=(+or-√265-11)/6
Case 1:
x =(√265-11)/6
Case 2:
x=(-√265-11)/6
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