Question

3 x + y = 19
3y + 5x=10 solve by substitution method​

Answer 1

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

How to solve

Step 1: we have given two Equations we will convert the whole Equation either in the form of x or y and make Equation 2

Step : Now, put the value of x or y into Equation 3 to find the value of other Variable say x or y.

➙3x+y= 19-----(1)

from equation 1

x= (19-y)÷3----(2)

➙3y+5x=10-------(3)

Put Equation 2 into the Equation 3

➙3y+5(19-y)/3=10

➙3y+95-5y/3=10

➙9y+95-5y=10×3

➙95+4y=30

➙4y= 30-95

➙4y=- 65

➙y= -65/4

y= -65/4

Put y's value into equation 2

x= 19-y/3

➙x= 19-(-65/4)÷3

➙x= 19+65/4÷3

➙x= 76+65/4÷3

➙x=141/4÷3

➙x=141/4×1/3

x= 47/4

Check:-

➙3x+y=19

Taking LHS

➙3(47/4)+(-65/4)

➙141/4-65/4

➙76/4= 19

Since,LHS = RHS(Verified)

Answer 2

Step-by-step explanation:

3y + 5x = 10 = 10-5x = 5x.

y = 5x -3y = 2xy

2) 3x + y = 19

19- 3x = 16xy ans