Question

3(x-y)^2 - 4x + 4y - 4

Answer 1

$3(x - y) ^{2} - 4x + 4y - 4$

$3(x - y) ^{2} - 4(x - y) - 4$

$let \: \: x - y \: \: be \: \: a$

$3a ^{2} - 4a - 4$

$3a ^{2} - (4 - 3)a- 4$

$3a ^{2} - 4a + 3a - 4$

$a(3a - 4) + 1(3a - 4)$

$(a + 1)(3a - 4)$

$(x - y + 1)(3x - 3y - 4)$

Answer 2

Step-by-step explanation:

Given

= 3(x-y)² - 4x+ 4y -4

It can be written as

= 3(x-y)² -4(x-y) -4

Assume (x-y)= a

Now , we get

= 3a²- 4a- 4

By middle term splitting method we get

= 3a²-6a+2a-4

= 3a(a-2)+2(a-2)

= (3a+2)(a-2)

Now put the value of a= (x-y)

= (3(x-y)+2)((x-y)-2)

Hope this helps you