Question

(3/x+y)+(2/x-y)=3,(2/x+y)+(3/x-y)=3 2/3

Answer 1

I hope rest you can solve.
Just put value of a and b.
Ok..

Answer 2

Step-by-step explanation:

equation1=(3/x+y)+(2/x-y)=3

let we take (3/x+y)=3×(1/x+y)

and (2/x-y)=2×(1/x-y)

assume that (1/x+y)=a, and (1/x-y)=b

now that (equation 1) will be

3a+2b=3

now 3a+2b-3=0. (equation-------1)

equation2=(2/x+y)+(3/x-y)=3×2/3

same take the equation like (1/x+y)=a, and (1/x-y)=b

now the (equation2) will be

2a+3b=11/3

now 6a+9b=11.

6a+9b-11=0. ( equation----------2)

now eliminate that equation 1 and 2

now ,

3a+2b-3=0. (equation-----1)

6a+9b-11=0. ( equation---2)

multiply (equation-----1) with 2 now

the equation will be

6a+4b-6=0. ( equation-----1)

6a+9b-11=0. (equation------2

-------------------

-5b+5=0

now we get b ,

-5b=-5

b=-5/-5

b=1

put this solution into any equation-----1 or 2 and u get a answer