Question

3^x+y= 3^2x-y=√27 then what will be the value of 3^x-y.​

Answer 1

Answer:x=1, y=1/2

Step-by-step explanation:

√27=3^3/2

So we get 2 eqns now.

3^x+y=3^3/2

and 3^2x-y=3^3/2

If base is same, we can equate powers.

So, x+y=3/2 and

2x-y=3/2.

Now we have 2 linear equations in 2 variables. I hope u can solve further.

Answer 2

Algebra

Given that,

3^(x+y) = 3^(2x-y) = sqrt 27 … [“sqrt” means square root]

So we can write

3^(x+y) = sqrt 27

=> 3^(x+y) = 3^(3/2)

=> x + y = 3/2 … (1)

Also,

3^(2x-y) = sqrt 27

=> 3^(2x-y) = 3^(3/2)

=> 2x - y = 3/2 … (2)

Adding equation 1 & 2 we can write

(x+y) + (2x -y) = (3/2) +(3/2)

=> 3x = 3

=> x = 1

Substituting x = 1 in equation 1 we get y = 1/2

So 3^(x-y) = 3^{1-(1/2)} = 3^(1/2) = 1.73205…

That’s it
Hope it helped
(O_o)