Question

3^(x+y) =81 and 81^(x-y) =3 , then find the values of x and y​

Answer 1

Answer:

here is your answer mate...

Step-by-step explanation:

3^x+y=81

81^x-y=3

If you add them, you get:

3^x+81^x=84

Trying out x=1, we get

3^1+81^1=84

3+81=81

If x=1, then

y=81–3^x=81–3=78

y=78

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Answer 2

Answer:

Step-by-step explanation:

3^x+y=81

81^x-y=3

If you add them, you get:

3^x+81^x=84

Trying out x=1, we get

3^1+81^1=84

3+81=81

If x=1, then

y=81–3^x=81–3=78

y=78

plz plz plz mark me as brainliest plzz