3^x = y² and y^x = 9
Solve for X and Y.
Answers
Answered by
0
Answer:
3^x=y^2
√3^x=y
y^x=9
x√9=y
Answered by
3
Answer :
(2 , 3) , (2 , -3) , (-2 , ⅓) , (-2 , -⅓)
Solution :
Here ,
The given equations are ;
3^x = y² ------(1)
y^x = 9 -------(2)
Squaring both sides of eq-(2) , we get ;
=> (y^x)² = 9²
=> y^(2x) = 81
=> (y²)^x = 81
=> (3^x)^x = 81
=> 3^(x²) = 81
=> 3^(x²) = 3⁴
=> x² = 4
=> x = √4
=> x = ±2
• If x = 2 , then using eq-(1) , we get ;
=> 3^x = y²
=> 3² = y²
=> 9 = y²
=> y² = 9
=> y = √9
=> y = ±3
• If x = -2 , then using eq-(1) , we get ;
=> 3^x = y²
=> 3^(-2) = y²
=> 1/3² = y²
=> 1/9 = y²
=> y² = 1/9
=> y = √(1/9)
=> y = ±⅓
Hence ,
(2 , 3) , (2 , -3) , (-2 , ⅓) , (-2 , -⅓) are the solutions of the given pair of equations .
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