Question

3 x-z 2 x 5 xtl x-1
$3x - 7 = x - 1 \div 2x - 5 = x + 1$
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Answer 1

Step-by-step explanation:

Therfore,

[tex]3x-7=\frac{x-1}{2x-5}\\ Therfore,\\ 2x-5(3x-7)=x-1\\ Therfore,\\ 6x^2-14x-15x+35=x-1\\ Therfore,\\ 6x^2-29x+35=x-1\\[/tex]

Now , since ,

[tex]x+1=x-1 \div 2x-5= \frac{x-1}{2x-5}\\ Therfore, \\ Therfore, \\ x+1= \frac{x-1}{2x-5}\\ Therfore , \\ 2x-5(x+1)=x-1\\ Therfore,\\ 2x^2+2x-5x-5=x-1\\ Therefore,\\ 2x^2-7x-5=x-1[/tex]

Since,

[tex]6x^2-29x+35=x-1 , 2x^2-7x-5=x-1\\ Therfore,\\ 6x^2-29x+35=2x^2-7x-5\\ Therfore,\\ (6x^2-29x+35)-(2x^2-7x-5)=0\\ Therfore,\\ 6x^2-29x+35-2x^2+7x+5=0\\ Therfore,\\ 4x^2-22x+40=0\\ [/tex]

U can now solve this by solving this simple quadratic equation

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