Question

3 x² – 2√6x + 2 = 0
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Answer 1

$3 {x}^{2} - 2 \sqrt{6} x + 2 = 0$

$3 {x}^{2} - \sqrt{6} x - \sqrt{6} x + 2 = 0$

$\sqrt{3} x( \sqrt{3} x - \sqrt{2} ) - \sqrt{2} ( \sqrt{3} x - \sqrt{2} )$

$( \sqrt{3} x - \sqrt{2} )( \sqrt{3} x - \sqrt{2} )$

Answer 2

Answer:

$3x2−26x+2=0</p><p></p><p>3 {x}^{2} - \sqrt{6} x - \sqrt{6} x + 2 = 03x2−6x−6x+2=0</p><p></p><p>\sqrt{3} x( \sqrt{3} x - \sqrt{2} ) - \sqrt{2} ( \sqrt{3} x - \sqrt{2} )3x(3x−2)−2(3x−2)</p><p></p><p>( \sqrt{3} x - \sqrt{2} )( \sqrt{3} x - \sqrt{2} )(3x−2)(3x−2)</p><p></p><p>$