Question

3. x2 + 3x - 10
please tell me the zero of this​

Answer 1

Answer:

$x ^{2} + 3x - 10 = 0 \\ \\ = > x^{2} + (5 - 2)x - 10 = 0 \\ \\ = > x ^{2} + 5x - 2x - 10 = 0 \\ \\ = > x(x + 5) - 2(x + 5) = 0 \\ \\ = > (x - 2)(x + 5) = 0 \\ \\ either \: x - 2 = 0 \\ \\ = > x = 2 \\ \\ or \: x + 5 = 0 \\ \\ = > x = - 5$

hope it helps u ✌

Answer 2

Step-by-step explanation:

x²+3x-10

x²+5x-2x-10

x(x+5) - 2(x+5)

(x+5) & (x-2)

therefore its zeroes are...

x= - 5 & x = 2

hope u got it... ☺️