Question

3(x² - y²)(y² - z²)(z² - x²)​

Answer 1

Answer:

Let P=(x²-y²) ³ + (y²-z²) ³ + (z²-x²) ³/(x-y) ³ + (y-z) ³ + (z-x) ³

as x^2-y^2+y^2-z^2+z^2-x^2=0

Thus numerator=3(x^2-y^2)*(y^2-z^2)*(z^2-x^2)

also in denominator x-y +y-z+z-x=0

so D=3(x-y)(y-z)(z-x)

Thus P=3(x^2-y^2)*(y^2-z^2)*(z^2-x^2) / 3(x-y)(y-z)(z-x)

=(x+y)(y+z)(z+x)