Math, asked by albinaby27, 6 months ago

3(y-2)= 2y - 1 - 3. pls tell pls
pls

Answers

Answered by Anonymous
3

Answer:

3(y-2) = 2y-1-3

or, 3y-6 = 2y-4

or, 3y-2y = -4+6

or, y = 2

Hence, y = 2.

Verify=

3(y-2) = 2y-1-3

or, 3(2-2) = (2×2)-1-3

or, 6-6 = 4-1-3

or, 0 = 0

Hence, L.H.S = R.H.S.

Answered by advayagiradkar
0

Answer:

Step-by-step explanation:

3(y-2) = 2y - 1 -2

= 3y - 6 = 2y - 1 - 2

= 3y - 2y -6 = -1 -2

= y = -4 + 6

= y = 2

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