Question

3(y^2-6) = y(y+7)-3​

Answer 1

Step-by-step explanation:

3(y²-6)=y(y+7)-3

3y²-18=y²+7y-3

3y²= y²+7y-3+18

3y²=y²+7y+15

-y²+3y²=7y+15

2y²=7y+15

= 7y+15-2y²

Answer 2

Step-by-step explanation:

3y^2-18=y^2+7y-3

3y^2-y^2-7y-18+3=0

2y^2-7y-15=0