3×+y=5 -------1
2x+3y=1 -------2
Answers
3x+y=5 -------(1)
2x+3y=1 -------(4)
Multiplying 3 with (1) and 1 with (2)
=> 9x + 3y = 15-------(3)
=> 2x + 3y = 1----------(4)
Subtracting (4) from (3):-
7x = 14
Hence x = 2
Substituting x in (1)
=> 6 + y = 5
Hence y = -1
Answer: x = 2, y = -1
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Correct Question:
3x + y = 5 --------- (1) [3x not 3×]
2x + 3y = 1 --------- (2)
Step-by-step explanation:
3x + y = 5 --------- (1)
2x + 3y = 1 -------- (2)
Multiply the eq (1) by 2 and eq (2) by 3
→ 3x + y = 5 (×2)
→ 6x + 2y = 10
→ 6x = 10 - 2 y -------- (3)
→ 2x + 3y = 1 (×3)
→ 6x + 9y = 3
→ 6x = 3 - 9y ----------- (4)
On comparing eq (3) & (4) we get,
→ 10 - 2y = 3 - 9y
→ 10 - 3 = - 9y + 2y
→ 7 = - 7y
→ y = -1
Substitute value of y = -1 in eq (1)
→ 3x + (-1) = 5
→ 3x - 1 = 5
→ 3x = 5 + 1
→ 3x = 6
→ x = 2
Therefore, the value of x is 2 and y is -1.