Question

3(y-5)/4-4y=3-(y-3)/2​

Answer 1

Step-by-step explanation:

$\frac{3(y - 5)}{4} - 4y = \frac{3 - (y - 3)}{2} \\ \frac{3y - 15}{4} - 4y = \frac{ 3 - y + 9}{2} \\ \frac{3y - 15 - 16y}{4} = \frac{12 - y}{2} \\ \frac{ - 13y - 15}{4} \frac{12 - y}{2} \\ 2( - 13y - 15) = 4(12 - y) \\ - 26y - 30 =48 - 4y \\ - 26y + 4y = 48 + 30 \\ - 22y = 78 \\ y = \frac{78}{ - 22} \\ y = - 3.54545$

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Answer 2

The correct answer is "y = -3". Further explanation is given below.

Step-by-step explanation:

Given equation is:

$\frac{3(y-5)}{4}-4y =3- \frac{(y-3)}{2}$

On taking LCM, we get

⇒  $\frac{3(y-5)-16y}{4} = \frac{6-(y-3)}{2}$

⇒ $\frac{3y-15-16y}{4} = \frac{6-y+3}{2}$

⇒ $\frac{-13y-15}{4}= \frac{9-y}{2}$

On applying cross-multiplication, we get

⇒  2(-13y-15) = 4(9-y)

⇒  -26y-30 =  36-4y

On adding "4y" on both sides, we get

⇒  -26y-30+4y =  36-4y+4y

⇒  -22y-30 = 36

On adding "30" on both sides, we get

⇒  -22y-30+30 = 36+30

⇒  -22y = 66

⇒   y = -$\frac{66}{22}$

⇒   y = -3

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