Math, asked by nishthakhanduja, 9 months ago

[3(y-5)/4]-4y=[3-(y-3)/2]​

Answers

Answered by amarlaldevarshi
1

Answer:

y=-27/2

Step-by-step explanation:

[3(y-5)/4]-4y=[3-(y-3)/2]

3y-15/4-4y=3-y-3/2

-y-15/4=6-y-3/2

-(y+15/4)=3-y/2

-(y+15/4)= -(y/2-3)

y+15/4=y/2-3

y-y/2= -3-15/4

y/2= -12-15/4

y/2= -27/4

y= -27*2/4

y= -27/2

Answered by prachigupta431
0

Answer:

3(y−5)÷4−4y=3−(y−3)÷2=)3(y−5)−16y=12−2(y−3)=)3y−15−16y=12−2y+6=)−13y−15=−2y+18=)−11y=33=)−y=1133=)y=−3

\huge{\red{\boxed{\boxed{\green{\underline{\sf{\green{y=-3}}}}}}}}y=−3

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